Notice: the signals with .are the operations which may cause the personal security. The signals with .. are the operations which may cause the machine damaging.
Time (Hour) = Battery capacity (AH) ÷ [Electrical power of using (W) ÷ q (V)], q depends on the battery voltage. Referring to the 12V battery, q = 10; referring to the 24V battery, q = 20. Such as the 12V DC input inverter uses the 12V battery. If the battery capacity is 50AH and at this time the inverter with 50W power load, then in the condition of the battery is full, according to the formula above: the battery use time = 50 (AH) ÷ [100 (W) ÷ 10 (V)] = 5 (Hour). That is batteries can be used for 5 hours.
1. Insert the inverter plug into cigarette light socket.
2. Turn on power switch. If the "Power" indicator is "ON", the Power Inverter works normally. If the "Fault" indicator is on, which means the Power Inverter is failure, check wire connections and appliance load.
3. Operation sequence: When turn on Power Inverter, first turn on Power Inverter and then turn on electric appliance; when turn off Power Inverter, first turn off electric appliance and then turn off Power Inverter.
Specifications (@20 °C)
| SUN-150/12-230 | SUN-150/24-230 | SUN-150/12-120 | SUN-150/24-120 |
Output Continuous Max. Power: | 150W |
Output Surge Power | 300W |
Converting Max. Efficiency | >85% | >90% | >85% | >90% |
Normal Input Voltage | DC12V | DC24V | DC12V | DC24V |
Input Voltage Range | DC10~15V | DC20~30V | DC10~15V | DC20~30V |
Output Voltage | AC230±5% | AC120±5% |
Output Frequency | 50Hz±2% | 60Hz±2% |
Output Wave Form | Modified Sine Wave |
No Load Current | <0.2A | <0.15A | <0.2A | <0.15A |
Input Under-voltage Cut Off Voltage: | 10±0.5V | 20±0.5V | 10±0.5V | 20±0.5V |
Input Over-voltage Cut Off Voltage: | 15±0.5V | 30±0.5V | 15±0.5V | 30±0.5V |
*: Measuring output voltage, please use the RMS Meter, or there will be errors between measurement and actual value. Idling current is measured under the rated input voltage.
Security features
There is the whole protection and audio-visual alarm system in the internal of SUN-150 power inverter. It can provide a full range of protection, mainly over-voltage protection, under-voltage protection, over-heat protection, overload protection, short circuit protection, reverse polarity protection.
Protection definition:
1.Under-voltage protection: When the input DC voltage is lower than the cut off under-voltage, the power inverter output will be cut off automatically.
2.Overvoltage protection: When the input DC voltage is higher than the cut off under-voltage, the power inverter output will be cut off automatically.
3.Overheat protection: When the internal temperature of power inverter is too high (about 85 ℃), the power inverter output will be cut off automatically.
4.Overload protection: When the power of electric apparatus which was brought by power inverter exceeded its maximum output, the output would be cut off automatically.
5.Short-circuit protection: When the output short-circuits, the power inverter output will be cut off automatically.
6.Reverse polarity protection: When the input positive and negative pole of the power inverter was connected reversed, it will fuse on the cigarette light plug head fuse to protect the internal circuits.
Working environment
1.Operation temperature: -10℃~40℃
2.Storage temperature: -40℃~85℃
3.Considerable air humidity should be less than 85%.
4.No electrical conductivity, dust explosion, corrosion-free gas in the working place.
5.No shock and vibration in the working place.
Physical properties
Size: 172 mm×78 mm×50 mm
Troubleshooting
Fault 1: No AC output
Reason | Solution |
●Vehicle's battery is not on | Turn the vehicle switch to the correct position |
●Connection between battery and the inverter is not well | Check repair or replace the connection or vehicle fuse |
●Low battery voltage | Check battery and charging circuit |
●The appliance's power is over the inverter’s power rating | Appliance’s power should not be over inverter’s power rating |
●Under-voltage protection of the inverter power | Charge the battery and switch it on again |
Fault 2:Low output voltage
Reason | Solution |
●The appliance’s power is over the inverter’s power rating | The appliance’s continuous power should not be over the inverter’s |
●Low battery voltage | Charge battery for enough energy |
.